0.1x^2=0.3+2.8

Solution for 0.1x^2=0.3+2.8 equation:

0.1x^2=0.3+2.8

We move all terms to the left:

0.1x^2-(0.3+2.8)=0

We add all the numbers together, and all the variables

0.1x^2-(3.1)=0

We add all the numbers together, and all the variables

0.1x^2-3.1=0

a = 0.1; b = 0; c = -3.1;
Δ = b2-4ac
Δ = 02-4·0.1·(-3.1)
Δ = 1.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.24}}{2*0.1}=\frac{0-\sqrt{1.24}}{0.2}
=-\frac{\sqrt{}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.24}}{2*0.1}=\frac{0+\sqrt{1.24}}{0.2}
=\frac{\sqrt{}}{0.2}
$